Series Resistance Calculator

Series Resistance Calculator

Add up to eight resistors in series with Rtotal = R1 + R2 + ... + Rn, then find the total current I = V divided by Rtotal that flows through every part, the voltage drop Vi = I times Ri across each resistor, the voltage distribution percentage, and the power Pi = I squared times Ri each one dissipates. You can also solve for a missing resistor needed to reach a target total.

Choose a Mode

🎯Real Series Circuit Presets

🔌Supply and Resistor Inputs

DC source driving the whole series string.

Missing R = target minus the sum of the others.

Unit applied to the target total above.

First resistor. Leave any resistor at 0 to skip it.

Second resistor in the chain.

Third resistor. Set to 0 if unused.

Fourth resistor. Set to 0 if unused.

Fifth resistor. Set to 0 if unused.

Sixth resistor. Set to 0 if unused.

Seventh resistor. Set to 0 if unused.

Eighth resistor. In missing mode, R8 is the unknown to solve.

Controls rounding on every result card.

Total Resistance 0 ohm sum of all series resistors
Total Current 0 A I = V / Rtotal, same in all
Largest Voltage Drop 0 V across the biggest resistor
Total Power 0 W P = V x I dissipated total

🔢Formula Snapshot

RtR1 + R2 + Rn
IV / Rtotal
ViI × Ri
PiI² × Ri

📋Series Circuit Rules and Properties

QuantitySeries BehaviorFormulaPlain Meaning
Total resistanceResistances addRt = R1 + R2 + ... + RnAlways larger than any single R
CurrentSame everywhereI = V / RtOne path, one current value
Voltage dropDivides by resistanceVi = I × RiBigger R takes a bigger share
Voltage sumDrops add to supplyV = V1 + V2 + ... + VnKirchhoff voltage law
Power per partSplits by resistancePi = I² × RiBigger R heats up more
Total powerSum of each partP = V × I = I² × RtAll heat comes from the source
DistributionProportional shareRi / Rt × 100Percent of the supply on each R

📏Equal Resistor Shortcut (n x R)

Count nEach ResistorRtotal = n x RI at 12 VDrop on Each
2100 ohm200 ohm60 mA6.0 V
3220 ohm660 ohm18.2 mA4.0 V
4470 ohm1.88 kohm6.38 mA3.0 V
5330 ohm1.65 kohm7.27 mA2.4 V
61 kohm6 kohm2.0 mA2.0 V
8150 ohm1.2 kohm10 mA1.5 V
10100 ohm1 kohm12 mA1.2 V

📊Voltage Distribution Example (12 V Supply)

ResistorValueShare Ri / RtVoltage DropPower at I
R11 kohm12.66 %1.52 V2.31 mW
R22.2 kohm27.85 %3.34 V5.08 mW
R34.7 kohm59.49 %7.14 V10.85 mW
Total7.9 kohm100 %12.0 V18.23 mW
Current I1.519 mAsame in allV / RtI² × Rt
Biggest dropR3 = 4.7 kohmlargest R7.14 Vmost heat

🔄Series vs Parallel Contrast

PropertySeries ConnectionParallel Connection
Total resistanceRt = R1 + R2 + ...1/Rt = 1/R1 + 1/R2 + ...
Compared to partsLarger than any resistorSmaller than any resistor
CurrentSame through all partsSplits between branches
VoltageDivides across partsSame across all branches
Two equal R2R totalR / 2 total
One part opensWhole circuit stopsOther branches keep working
Common useVoltage dividers, stringsLoad sharing, power rails

🗃Series Combination Comparison Grid

CombinationRtotalI at 12 VBiggest DropTotal PowerNote
1k + 1k2 kohm6.00 mA6.0 V each72 mWEqual 50 / 50 split
220 + 220 + 220660 ohm18.18 mA4.0 V each218 mWThree equal thirds
1k + 2.2k + 4.7k7.9 kohm1.52 mA7.14 V (4.7k)18.2 mWDivider chain
330 + LED (approx 470)800 ohm15.0 mA7.05 V (470)180 mWLED drop modeled
470 x 41.88 kohm6.38 mA3.0 V each76.6 mWEven string of four
100 x 101 kohm12.0 mA1.2 V each144 mWTen equal steps
150 + 100250 ohm48.0 mA7.2 V (150)576 mWUneven two-part
47 + 47 (ballast)94 ohm127.7 mA6.0 V each1.53 WCurrent-limit stack
10 + 1020 ohm600 mA6.0 V each7.2 WHigh-current heaters
1M + 1M2 Mohm6.0 uA6.0 V each72 uWHigh-impedance divider

Formula Breakdown

Rtotal = R1 + R2 + ... + RnSeries resistances simply add. A 1 kohm and a 2.2 kohm and a 4.7 kohm in series give Rt = 1000 + 2200 + 4700 = 7900 ohm.
Current I = V / RtotalOne current flows through the whole string. With 12 V across 7900 ohm, I = 12 / 7900 = 0.001519 A, about 1.519 mA.
Voltage drop Vi = I × RiEach resistor drops current times its own value. The 4.7 kohm drops 0.001519 × 4700 = 7.14 V, the largest share.
Distribution = Ri / Rt × 100The 4.7 kohm is 4700 / 7900 = 59.5 % of the total, so it takes 59.5 % of the supply voltage.
Power Pi = I² × RiHeat in each part scales with resistance. The 4.7 kohm dissipates 0.001519² × 4700 = 10.85 mW.
Total power P = V × IAll heat comes from the source: P = 12 × 0.001519 = 18.2 mW, equal to I² × Rt.
Missing R = target − sum(others)To reach a 10 kohm target from 1k + 2.2k already placed, the missing resistor is 10000 − 3200 = 6800 ohm.

💡Series Design Tips

Size the biggest resistor first: In a series string the largest resistor always drops the most voltage and dissipates the most power. In the 1k + 2.2k + 4.7k chain on 12 V, the 4.7 kohm alone takes 7.14 V and 10.85 mW, roughly 60 percent of everything. Pick that part rating before the smaller ones so it never runs hot.
Check the current, not just the sum: Because I = V / Rtotal is shared by every part, low-resistance strings pull big currents. Two 10 ohm resistors on 12 V total only 20 ohm, so I = 0.6 A and the pair burns 7.2 W. Always verify that shared current stays inside each resistor and each wire rating.

A series connection is simply you placing components in line with each other. In this case, all of parts become a longer part, an extended obstacle that electrons has to get around. Electricity does not care what you want; it just cares about the overall resistance. You plug in your values and let calculator do the rest. It will then tell you precisely how many volts go where and which component has to shed how much heat.

In a series string, there’s only one way for current to go. It can’t jump over first resistor and get to second. And it can’t take short cuts past others. The path is unique so the amount of resistance the whole thing has is simply addition of each separate resistor. No fancy equations required here. A 1 kilohm plus a 2 kilohm in series gives circuit a total of 3 kilohms. That total determine how much current flows through entire circuit. The supply voltage divided by total resistance equates to current.

How Series Circuits Work

All components in the chain recieve the same exact current. Larger resistors hog more of the juice. Series circuits is predictable because of this consistency. They’re also unforgiving. Different voltages are distribute differently. The current remains constant. But, it doesn’t mean that every resistor will get the same amount of voltage drop. That depends on its size compared to other resistor.

The tool shows you the percentages of how much of supply voltage is distributed where. When you put a large resistor like a 4.7 kilohm next to a small one like 100 ohms, big guy will take almost whole supply voltage. The little dude will see almost no voltage drop at all. Check it out with Ohm’s law applied to both components. Viewing it as a percentage makes it easier to understand what each piece of resistance is doing.

The highest is taking the most voltage and running hottest. That is important if you are choosing wattage rating. The same proportional rule apply to power dissipation. Power dissipated in heat is directly proportional to resistance, because current is constant. So if one resistor is the highest value, then that’s the biggest resistor doing the most work. That means it will also produce most heat.

A good tip: Always size the big component first. If you use a power resistor with a rating that is too small for largest load, it would of burn out before smaller resistors even get hot. You can see how this breaks down in calculator. It lets you know who needs bigger package. Sometimes we assume they will share equally but that is not true if there are large differences between them.

But then there’s that situation where you have a standard value on hand but are looking for missing piece to reach your target total. That’s a common occurrence during design when you want to add some component to an existing circuit and only have a standard value available. In that case you are reverse engineering your way to a solution. The missing resistor mode does just that: it subtracts known components from desired total.

So if you have 3.2k ohms installed and you want 10 kilohms total, it can tell you exactly what you’re missing so you can get precisely there. That’s a useful feature for tweaking LED current or trimming down a voltage divider without having to purchase several prototype boards.

Once you understand how things behave in series, it starts to change the way you think about reliability. One thing about a parallel circuit: if one branch fails others continue functioning. With a series circuit, any open connection shuts down everything. It becomes a single point of failure throughout entire chain. That’s the trade-off you make with simplicity and fragility in design of systems.

You go with series connections because they will divide voltage naturaly and restrict current predictably. But you’re accepting that there will be a fragility to continuity. The tool lets you balance those out by visualizing impact on power loss and current draw in real-time. Control is the end game. You send some safe current through that LED and certain voltage to that sensor.

Use arithmetic precision to dial it all in with resistors in series. You understand how changes rippled through circuit because you thought of it as a single thing instead of a bag of parts. Not only do resistors alter one value; they shift the power load and voltage distribution on each component. That’s what makes a good design hold up in the real world vs it is merely functional. The calculator provides the numbers. Knowing how those things relate to each other assures you that it will stand up to reality.

Series Resistance Calculator