Beam Load Calculator

Beam Load Calculator

Analyze a simply supported beam in seconds. Enter the span, load and section, and this tool returns the support reactions, maximum shear force, peak bending moment and midspan deflection for a central point load, a full-span uniform load or an offset point load, then checks the sag against common L/360 and L/240 serviceability limits.

šŸ› Choose a Load Case

šŸŽÆReal Beam Load Presets

šŸ“Beam and Load Inputs

Clear distance between the two supports, in meters.

Concentrated load for point cases (see unit at right).

Applies to P. 1 kN = 1000 N.

Uniform load per meter for the UDL case.

Applies to w. Total W = w Ɨ L.

Offset case only. Distance a from the left support; b = L āˆ’ a.

Choosing a material fills the modulus of elasticity E.

Young's modulus in pascals. 1 GPa = 1e9 Pa.

Second moment of area of the section, in m⁓.

Deflection limit the result compares against.

Max bending moment 0 kN*m peak M along the beam
Max shear force 0 kN at the support
Support reactions 0 kN R1 and R2
Max deflection 0 mm midspan sag and L/d

šŸ”¢Formula Snapshot

RP/2 or wL/2
MPL/4 or wL²/8
dPL³/48EI
L/dvs L/360

šŸ“‹Simply Supported Beam Formulas by Case

Load CaseReactions RMax Shear VMax Moment MMax Deflection d
Central point load PP/2 eachP/2P*L/4P*L³ / (48 E I)
Uniform load w over Lw*L/2 eachw*L/2w*L² / 85 w L⁓ / (384 E I)
Offset point load at aR1 = P*b/L, R2 = P*a/Lmax(R1, R2)P*a*b / LP a² b² / (3 E I L)
Two equal loads at thirdsP eachPP*L/323 P L³ / (648 E I)
Triangular load, peak w0w0*L/6 and w0*L/3w0*L/30.1283 w0 L²0.01304 w0 L⁓ / (E I)

🧩Modulus of Elasticity E for Common Materials

MaterialE (GPa)E (Pa)Relative StiffnessTypical Use
Structural steel200200e9Very highBeams, columns, frames
Stainless steel193193e9Very highCorrosion-resistant members
Titanium alloy116116e9HighAerospace, light structures
Cast iron100100e9HighLegacy columns, bases
Aluminum6969e9MediumLight beams, decks, rails
Concrete (normal)3030e9Low-mediumSlabs, lintels, beams
Glulam / LVL timber1313e9LowEngineered wood beams
Douglas fir / wood1111e9LowJoists, rafters, headers

šŸ“Typical I Values for Sample Sections

SectionDimensionsFormulaI (m⁓)Notes
Rectangleb 50 Ɨ h 150 mmb h³ / 121.41e-5Timber joist on edge
Rectangleb 100 Ɨ h 300 mmb h³ / 122.25e-4Deep wood / glulam beam
Solid square100 Ɨ 100 mma⁓ / 128.33e-6Post or small column
Solid roundd 100 mmĻ€ d⁓ / 644.91e-6Round bar or pin
Steel W150x24 (approx)150 mm deepTabulated1.34e-5Light wide-flange
Steel W250x33 (approx)250 mm deepTabulated4.90e-5Common floor beam
Steel W310x39 (approx)310 mm deepTabulated8.00e-5Default in this tool
Steel W410x46 (approx)410 mm deepTabulated1.56e-4Longer-span floor beam

šŸ—ƒSpan vs Moment and Deflection Comparison Grid

Span LM point = PL/4d point = PL³/48EIM UDL = wL²/8d UDL = 5wL⁓/384EIL/d point
2 m5 kN*m0.13 mm2.5 kN*m0.03 mmL/15400
3 m7.5 kN*m0.44 mm5.6 kN*m0.13 mmL/6840
4 m10 kN*m1.04 mm10 kN*m0.42 mmL/3850
5 m12.5 kN*m2.03 mm15.6 kN*m0.81 mmL/2460
6 m15 kN*m3.52 mm22.5 kN*m1.41 mmL/1710
8 m20 kN*m8.33 mm40 kN*m3.33 mmL/960

Basis: P = 10 kN point OR w = 5 kN/m UDL, steel E = 200 GPa, I = 8e-5 m⁓. Notice UDL sag stays smaller and point sag climbs steeply with span.

āœ…Deflection Serviceability Limits

LimitRatioAllowed d at L = 4 mAllowed d at L = 6 mTypical Application
L/180Loose22.2 mm33.3 mmRough framing, total load
L/240General16.7 mm25.0 mmRoofs, floors total load
L/360Standard11.1 mm16.7 mmFloors, live load, plaster
L/480Strict8.3 mm12.5 mmBrittle finishes, tile
L/600Very strict6.7 mm10.0 mmSensitive equipment

āš™Formula Breakdown

Reactions R1 = R2 = P/2For a central point load the beam is symmetric, so each support carries half the load. A 10 kN load gives 5 kN at each end.
Point moment M = P*L/4The bending moment peaks under the load at midspan. P = 10 kN over L = 4 m gives M = 10 Ɨ 4 / 4 = 10 kN*m.
Point deflection d = P L³ / 48EIMidspan sag for a central point load. It rises with the cube of the span, so doubling L multiplies sag by eight.
UDL reactions R = w*L/2A uniform load of total W = w Ɨ L splits evenly, so each support takes half of the total distributed load.
UDL moment M = w*L²/8Peak moment at midspan for a full-span uniform load. w = 5 kN/m over 4 m gives M = 5 Ɨ 16 / 8 = 10 kN*m.
UDL deflection d = 5wL⁓/384EIMidspan sag for a uniform load grows with the fourth power of the span, even steeper than a point load.
Offset moment M = P*a*b/LFor a load at distance a with b = L āˆ’ a, the moment peaks under the load. Reactions become R1 = P b / L and R2 = P a / L.
Deflection ratio L / dDivide span by sag and compare to the limit. L = 4 m with d = 1.04 mm gives L/3846, far inside an L/360 floor limit.

šŸ’”Beam Load Design Tips

Spread the load out: A central point load produces a peak moment of P*L/4, but taking that SAME total load and spreading it evenly as a UDL gives only W*L/8, exactly half the peak moment. Distributing weight, or adding intermediate supports, is one of the gentlest ways to cut bending stress in a beam without changing the section.
Watch the span exponent: Deflection grows with the CUBE of span for a point load and the FOURTH power for a UDL, so doubling the span can multiply sag 8x to 16x while the moment only grows with L or L squared. Always check BOTH strength (moment and stress) and serviceability (deflection limits like L/360), because a beam that is strong enough can still sag too far to feel safe or protect finishes.

The beam is adequate in strength to support the weight of the roof, yet it’s too saggy (meaning it lacks stiffness) for your livig room ceiling. It may seem unlikely, but it’s more common then you’d expect, particularly if you’re inspecting an aged floor joist that sags beneath your feet or sizing a header across newly cut doorway. A beam must be stiff as well as strong. One prevents collapse; the other prevents trampoline-like behavior.

The calculator up top account for this tug-of-war between stiffness and strength, without making you derive it from scratch each time you sketch out a rough idea. From there we move to more complex structures: the classic one would be a simply supported beam resting on two supports which push upwards on it but do not oppose its rotation. They is effectively a roller on one end and a pin on the other, allowing the member to swing freely with no buildup of complicated end moments.

Why Beams Need Strength and Stiffness

So the physics becomes simple. There are equal and opposite reactions upwards at both ends balancing the total downwards load. That’s the simple vertical balance that all calculations come from. There is four different stories those outputs tell you about that balance. The reactions show you how hard the supports must push up. The shear force tells you what the inside of the beam are doing as it tries to slice itself apart around those supports. The bending moment measure the amount of curling action the load has on the member. It makes the member want to curl into a U. This tell you how deep or how thick a section you will need. Deflection is the sag you see, the part that cracks plaster and worries your neighbors.

It’s the one you worry about, but you need them all to feel good about your design. Where you load it matter. Maximum bending moment happen at the worst case: a concentrated heavy load dead center. Stress peaks immediately below this load. Uniformly distribute the same total load across your span (the distributed load), and it will drop your maximum moment in half. That’s the benefit of increasing intermediate support points, or distributing a machine weight across a wider bearing plate. It’s also one of the least expensive ways to reduce stress without purchasing an oversized beam. You can select from these cases with the calculator and get a direct comparison of how much distribution relieves your span.

Span length is the silent killer in beam design. A longer span does not deflect proportionally to its length. Sag increases with the cube of the span for a point load. So when you double the span length, the sag becomes eight times greater. When under a uniform load, deflection increases at the rate of the fourth power. So doubling the span result in sixteen times the sag. On the other hand, the moment only increases by the square (or less) of the span. Hence a short beam can be quite rigid compared to a long beam of the exact same steel.

As far as material goes, not only does it matter for strength, but also for stiffness. For example, steel has an extremely high modulus of elasticity which means it’s very rigid. On the other hand aluminum will bend significantly further under the same load due to its lower stiffness but it’s also light. Depending on wood type and grade, it’s somewhere in-between. These is available in the reference table on the page. That way you can swap out materials and get a feel for the impact to the ultimate sag.

Geometry isn’t something that should of be ignored either. Depth plays a large role here since it’s cubed in the equation for moment of inertia. So while a wide beam may resist bending well, a deep one resists bending MUCH better. There are serviceability limits (L/360) for good reason. They ensure floors do not bounce and ceilings do not crack. You can build comfortabley buildings only when your deflection meets those ratios, and you shouldn’t compromise on that. The tool will automatically check yours against them and flag it if you’re over.

It’s easy to build for strength without thinking about comfort. Do both. Combining strength with a solid appearance is what turns your sketch into a safe building.

Beam Load Calculator