Capacitive Reactance Calculator – Xc = 1/(2 pi f C)

Capacitive Reactance Calculator

Find capacitive reactance with Xc = 1 / (2 pi f C) in ohms, then solve backwards for the capacitance or frequency you need. Enter an optional AC voltage to get the current I = V / Xc. Reactance falls as frequency or capacitance rises, and the current through an ideal capacitor leads the voltage by 90 degrees.

Real Circuit Presets

🔢Reactance Inputs

Pick the unknown; the matching field below is disabled.

AC signal frequency. At 0 Hz (DC) reactance is infinite.

1 kHz = 1000 Hz, 1 MHz = 1,000,000 Hz.

Value marked on the capacitor. Larger C lowers Xc.

1 uF = 1000 nF = 1,000,000 pF.

Used when you solve for capacitance or frequency.

RMS volts. Leave 0 to skip the current result.

Controls rounding on every result card.

Capacitive Reactance Xc 0 ohm opposition to AC current
AC Current I = V / Xc 0 A from applied AC voltage
Phase Relationship -90 deg current leads the voltage
Solved Unknown 0 ideal cap uses zero real power

📏Formula Snapshot

Xc1 / (2 pi f C)
C1 / (2 pi f Xc)
f1 / (2 pi C Xc)
IV / Xc

📈Reactance vs Frequency for 1 uF

FrequencyAngular 2 pi fReactance XcBehaviour
0 Hz (DC)0 rad/sInfiniteBlocks DC
20 Hz126 rad/s7958 ohmVery high
50 Hz314 rad/s3183 ohmMains low end
60 Hz377 rad/s2653 ohmMains US
1 kHz6283 rad/s159.2 ohmAudio mid
10 kHz62832 rad/s15.92 ohmAudio high
100 kHz628 krad/s1.592 ohmNear short
1 MHz6.28 Mrad/s0.159 ohmRF, tiny Xc

📊Reactance at 1 kHz Across Capacitor Values

CapacitanceTypical UseXc at 1 kHzXc at 100 kHz
10 pFRF trimmer15.9 Mohm159 kohm
100 pFRF coupling1.592 Mohm15.92 kohm
1 nFFilter cap159.2 kohm1592 ohm
10 nFSnubber15.92 kohm159.2 ohm
100 nFDecoupling1592 ohm15.92 ohm
1 uFCoupling159.2 ohm1.592 ohm
10 uFBulk bypass15.92 ohm0.159 ohm
470 uFSMPS output0.339 ohm0.0034 ohm

🔌Frequency and Capacitance Comparison Grid

FrequencyCapacitanceReactance XcI at 10 VPhaseNote
50 Hz1 uF3183 ohm3.14 mAI leads 90Mains filter
60 Hz10 uF265.3 ohm37.7 mAI leads 90PFC cap
440 Hz1 uF361.7 ohm27.6 mAI leads 90Audio tone
1 kHz100 nF1592 ohm6.28 mAI leads 90Coupling
10 kHz100 nF159.2 ohm62.8 mAI leads 90Audio high
100 kHz10 nF159.2 ohm62.8 mAI leads 90Snubber
100 kHz470 uF0.0034 ohm2954 AI leads 90SMPS bulk
1 MHz100 pF1592 ohm6.28 mAI leads 90RF bypass
1 MHz100 nF1.592 ohm6.28 AI leads 90Decouple
10 MHz100 pF159.2 ohm62.8 mAI leads 90HF bypass

🔄Unit Multipliers Used

UnitSymbolIn Base UnitApplies To
HertzHz1 HzFrequency
KilohertzkHz1000 HzFrequency
MegahertzMHz1000000 HzFrequency
PicofaradpF1e-12 FCapacitance
NanofaradnF1e-9 FCapacitance
MicrofaraduF1e-6 FCapacitance

Formula Breakdown

Xc = 1 / (2 pi f C)Capacitive reactance in ohms. For 1 uF at 50 Hz: Xc = 1 / (2 × 3.1416 × 50 × 0.000001) = 3183 ohm.
C = 1 / (2 pi f Xc)Rearrange for capacitance. To get 1000 ohm at 1 kHz: C = 1 / (2 pi × 1000 × 1000) = 159 nF.
f = 1 / (2 pi C Xc)Rearrange for frequency. A 1 uF cap reaches 159 ohm at f = 1 / (2 pi × 0.000001 × 159) = 1 kHz.
I = V / XcOhms law for AC. With 230 V across 3183 ohm the current is I = 230 / 3183 = 72.3 mA.
Phase = -90 degreesIn an ideal capacitor the current leads the applied voltage by 90 degrees, so voltage lags current.
Real power = 0 WBecause current and voltage are 90 degrees apart, an ideal capacitor stores and returns energy and dissipates no real power.

💡Practical Capacitor Tips

Caps block DC and pass AC: As frequency falls toward 0 Hz the reactance Xc rises toward infinity, so a capacitor blocks steady DC completely. As frequency rises Xc drops, which is why a 100 nF decoupling cap looks like about 1592 ohm at 1 kHz but only 1.6 ohm at 1 MHz and behaves almost like a short to high frequency noise.
Current leads voltage by 90 degrees: The current into a capacitor peaks a quarter cycle before the voltage, a phase of -90 degrees. Because the two are in quadrature the ideal capacitor dissipates zero real watts; the energy is only stored and returned. Choose voltage and ripple ratings, not just capacitance, for real designs.

This is a capacitive reactance calculator. This is another useful calculator based off a basic relationship among AC electronics. Xc is capacitive reactance, or how much a capacitor opposes an alternating current flow. That’s expressed by the formula Xc = 1 / (2 pi f C). The result of that calculation are in ohms.

Unlike a simple resistor, however, capacitive reactance vary with frequency. The higher the frequency, the lower the capacitor’s reactance. This calculator computes all aspects of the formula. If you know any two variables, it will solve for remaining one. It changes the formula so you can calculate either the required capacitance or frequency.

How to Use This Calculator

And if you provide a voltage across the part, it calculates the AC current flowing through component using the formula: I = V / Xc. Both reactance and resistance is expressed in ohms. Both act as a limiting force on current. However, resistance is due to loss of energy, while reactance is due to storage of energy. For example: In a capacitor, there’s charge stored in an electric field that gets released with each cycle. Because of this, the capacitor resists change in voltage; it doesn’t waste power.

One equation says this all: Xc = 1 / (2 pi f C). That’s where we get two things in one shot. One, the bigger the capacitance, C, the greater amount of charge for any given amount of voltage. Which lowers the reactance. Two, the faster the frequency, f, the less chance the capacitor has to charge up before the voltage reverses polarity (which also lowers the reactance).

Put in a 1 microfarad capacitor at 50 hertz and the calculator spits back about 3183 ohms. Push the frequency up to 1 kilohertz and the same part drops down to around 159 ohms. The equation Xc = 1 / (2 pi f C) connects three variables. Given any two, you get the third.

You can use the solve for selector to choose which variable you want to find. Select reactance and you put in the frequency and capacitance and instantly have the reactance right there. Select capacitance and the tool swaps to C = 1 / (2 pi f Xc), letting you answer that all too frequent design problem: What capacitance do I need to get a certain reactance at this frequency?

Select frequency and it calculates the f = 1 / (2 pi C Xc) point where a particular capacitor reaches the selected reactance. That’s the basis for setting a filter corner. The input fields never conflict, so the one being solved for is disabled.

With the reactance value in hand, Ohm’s law for ac yields the current from I = V / Xc. Simply enter the RMS voltage that you supply and the calculator computes the current. It does so in such a way that the displayed number remains reasonable, using either amps, milliamps, or microamps.

The other result of equal importance is the phase. For an ideal capacitor, the current will lead the voltage by 90 degrees, or a quarter of a cycle. The tool displays this as a phase of -90 degrees. Since the voltage and current are 90 degrees apart, there is no dissipation of energy, just storage and return. Therefore, the real power is zero watts. This means that coupling and bypass capacitors can conduct large current with little to no warming.

Consider an audio stage operating at 10 kilohertz with a 100 nanofarad coupling capacitor. Use Xc = 1 / (2 pi f C) to plug in the numbers. 2 pi f, the angular frequency, is approximately 62832 radians per second. Multiply that by 100 nanofarads and invert for approximately 159 ohms. With a 1 volt signal across this, we have current equal to I = 1 / 159 or approximately 6.3 milliamps with the current leading the voltage by 90 degrees.

Lowering the frequency down to 1 kilohertz increases the reactance by a factor of ten to around 1592 ohms. Therefore, the same capacitor allows much less low frequency signal through. This frequency dependency is precisely why capacitors are used as DC blocks and also make them high pass elements.

The results is presented on four cards. The first is the reactance card, which shows Xc in ohms, kilohms, or megohms, depending on the size of the capacitor. The second is the current card: I = V / Xc if you input a voltage; it warns you if you don’t. The third card shows phase, reminding you that the current leads and always stays at the same angle (fixed at -90 degrees). The fourth card repeats whatever the requested unknown was, whether it’s capacitance or frequency in reverse-mode.

You get a nice note saying “ideal capacitor dissipates no real power.” Then there’s a breakdown panel listing all the numbers that were substituted one-by-one. In other words, it lets you check your own hand calculations, too.

The calculator takes frequency (hertz, kilohertz, megahertz) and capacitance (microfarads, nanofarads, or even picofarads), mixing different scales used in real circuits. The calculator converts all inputs to base units internally. One megahertz is a million hertz. One kilohertz is 1000 hertz. A microfarad is a million picofarads or 1000 nanofarads.

The reference tables walk through reactance for a 1 microfarad capacitor across a full frequency sweep. Then they show the drop off in reactance of the capacitor with higher values at both 1 kHz and 100 kHz. A broad table compares frequency vs. Capacitance against reactance, phase, current at 10 volts, and a typical application note.

Real world scenarios are loaded as presets which calculate instantly. For instance, a DC blocking capacitor; a snubber at 100 kilohertz; a mains filter cap at 50 hertz; an RF bypass at 1 megahertz; a power factor capacitor at 60 hertz; an audio coupling cap at 10 kilohertz; a decoupling cap and a switching supply output capacitor. To show that the reverse works, there are two more presets. One calculates the capacitance for 1 kilohertz at 1000 ohms. And the other calculates the frequency of a 1 microfarad part at 159 ohms.

The fastest method to develop some sense of how reactance changes is to start from one of the presets and nudge the values. A dropped decimal is a quiet wrecking ball for any power supply, coupling network or filter. This calculator covers both design and analysis with one equation: Xc = 1/(2 pi f C), and all its rearrangements, plus current relationship of I=V/Xc all in one space. Those are the two anchors.

A capacitor does not conduct DC because at zero hertz the reactance is infinity. The higher the frequency, the lower the reactance. This means that as frequency rises, more and more AC is passed, but the current always lags the voltage by 90 degrees. Select a preset, adjust the input, and read the cards to get a breakdown of trustworthy numbers within seconds.

You should of used this sooner. It’s moddern technology.

Capacitive Reactance Calculator – Xc = 1/(2 pi f C)